3m^2+11m+12=4

Solution for 3m^2+11m+12=4 equation:

3m^2+11m+12=4

We move all terms to the left:

3m^2+11m+12-(4)=0

We add all the numbers together, and all the variables

3m^2+11m+8=0

a = 3; b = 11; c = +8;
Δ = b2-4ac
Δ = 112-4·3·8
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-5}{2*3}=\frac{-16}{6}
=-2+2/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+5}{2*3}=\frac{-6}{6}
=-1
$